Quantitative Aptitude Question:
A work is done by two people in 24 min. one of them can do this work a lonely in 40 min. how much time required to do the same work for the second person?
Answer:
let A does the work in 40 mins (given)
let B does the work in x mins
amt of work done by A in 1 min = 1/40
amt of work done by B in 1 min = 1/x
amt of work done jointly by both A & B = 1/24
which implies (1/40)+(1/x) = (1/24)
on solvin the above eqn. for x we get
x = 60
let B does the work in x mins
amt of work done by A in 1 min = 1/40
amt of work done by B in 1 min = 1/x
amt of work done jointly by both A & B = 1/24
which implies (1/40)+(1/x) = (1/24)
on solvin the above eqn. for x we get
x = 60