Analytical Interview Preparation Guide Download PDF
Analytical frequently Asked Questions in various Analytical job Interviews by interviewer. The set of Analytical interview questions here ensures that you offer a perfect answer to the interview questions posed to you. Get preparation of Analytical job interview
59 Analytical Questions and Answers:
1 :: A camel must travel 15 miles in order to reach the nearest city. She have 45 bananas with her but can carry only 15 at a time. Also she eat 1 banana /mile. Then the maximum no of bananas that can be transported to the city?
a) 4
b) 6
c) 8
d) 12
6 Bananas can be transported to the city.
The camel carries 15 bananas for a kilometer and comes back (15 bananas becomes 13). It carries the second set of 15 bananas for a kilometer and comes back (15 bananas becomes 13). It carries the third set of 15 bananas for a kilometer (15 bananas becomes 14). Now we have 40 bananas which has to be carried for 14 kilometers.
At the end of the second kilometer the total number of bananas becomes 35.
At the end of the third kilometer the total number of bananas becomes 30.
At the end of the fourth kilometer the total number of bananas becomes 25.
At the end of the fifth kilometer the total number of bananas becomes 20.
At the end of the Sixth kilometer the total number of bananas becomes 15.
The camel carries the remaining 15 bananas for the last 9 more kilometers; and by the time it reaches its destination, it has consumed 9 bananas -- The remaining is 6 Bananas
The camel carries 15 bananas for a kilometer and comes back (15 bananas becomes 13). It carries the second set of 15 bananas for a kilometer and comes back (15 bananas becomes 13). It carries the third set of 15 bananas for a kilometer (15 bananas becomes 14). Now we have 40 bananas which has to be carried for 14 kilometers.
At the end of the second kilometer the total number of bananas becomes 35.
At the end of the third kilometer the total number of bananas becomes 30.
At the end of the fourth kilometer the total number of bananas becomes 25.
At the end of the fifth kilometer the total number of bananas becomes 20.
At the end of the Sixth kilometer the total number of bananas becomes 15.
The camel carries the remaining 15 bananas for the last 9 more kilometers; and by the time it reaches its destination, it has consumed 9 bananas -- The remaining is 6 Bananas
2 :: A cube is painted black. It is divided into 125 equal cubes. Find the number of cubes, which have at least 2 sides painted black?
80 squares have atleast 2 of their sides painted
3 :: You have been given a toaster to test. There are no user instructions. What will you test and why? What expected behaviors do you expect to observe? How would you classify the tests?
Please share your answers.
4 :: Select the odd one
(a) January
(b) February
(c) Wednesday
(d) November
ans is november bcoz jan,wed,feb r ends with ' y' whereas nov ends with ' r '
5 :: A Father, son and grandson are walking in the park. A man approaches them and asks for their age. The Father replies, "My son is as many weeks as my grandson is in days, and my grandson is as many months old as I am in years. We are all 100 years together.
60,35,5?
The detail solution to this question is like this.
Let's Say father's age in year is Y yr. Son's age in weeks is x week, which if converted to year is 7x/365yr. Now as per the question,
The Father replies, "My son is as many weeks as my grandson is in days
so grandson's age in days is X days.,which if converted to year is x/365 yr.
So 1st equation: y+7x/365+x/365 = 100....................(1)
Father says My grandson is as many months old as I am in years.
means, grandson is y months old,b'coz father is y yrs old.So equating grandson's age in days(x days) from above statement with his age in months (y month),both converted in years, gives us
x/365 = y/12.......................(2)
solving these two equations gives y=60 in years,that is father' age.grandson is as many months old as father is in years.So grandson's age is 60 months,i.e 5yrs,which converted to days is 1825 days.As son's age is as many weeks as grandson's age is in days.So son's age is 1825 weeks,that is converted in yrs is 1825*7/365=35yrs.
father 60yrs
son 35yrs
Grandson 5yrs
Let's Say father's age in year is Y yr. Son's age in weeks is x week, which if converted to year is 7x/365yr. Now as per the question,
The Father replies, "My son is as many weeks as my grandson is in days
so grandson's age in days is X days.,which if converted to year is x/365 yr.
So 1st equation: y+7x/365+x/365 = 100....................(1)
Father says My grandson is as many months old as I am in years.
means, grandson is y months old,b'coz father is y yrs old.So equating grandson's age in days(x days) from above statement with his age in months (y month),both converted in years, gives us
x/365 = y/12.......................(2)
solving these two equations gives y=60 in years,that is father' age.grandson is as many months old as father is in years.So grandson's age is 60 months,i.e 5yrs,which converted to days is 1825 days.As son's age is as many weeks as grandson's age is in days.So son's age is 1825 weeks,that is converted in yrs is 1825*7/365=35yrs.
father 60yrs
son 35yrs
Grandson 5yrs
6 :: Select the antonym of capture from the following
(a) attack
(b) Release
(c) condemn
(d) None of the above
answer is release
7 :: Is the meaning of Credible and Credulous,
(a) same
(b) contradictory
(c) no relation
no relation (one is believed other is about to believe)
8 :: Next number in the series 1, 1/2, 1/4, 1/8?
1/16
The next number is 1/16.
Becoz The diff b'ween 1/2 and 1/4 is "+2"
and next 1/4 and 1/8 is "+4"
means 1 1/2 (+2) 1/4 (+4) 1/8 (+8) 1/16
Becoz The diff b'ween 1/2 and 1/4 is "+2"
and next 1/4 and 1/8 is "+4"
means 1 1/2 (+2) 1/4 (+4) 1/8 (+8) 1/16
9 :: A clock is late by 1 minute 27 seconds in a month. Then how much will it be late in 1 day?
2.9 seconds
1min=60sec, so 1min 27 secs is=60+27=87
then 1 month=30days
now, 30days=87secs late
1day = ? x
x = (87*1)/30=2.9 secs
Ans: 2.9 secs per day it will be late.
then 1 month=30days
now, 30days=87secs late
1day = ? x
x = (87*1)/30=2.9 secs
Ans: 2.9 secs per day it will be late.
10 :: Y catches 5 times more fishes than X. If total number of fishes caught by X and Y is 42, then number of fishes caught by X?
7
let no. of fish x catches=p
no. caught by y =r
r=5p.
r+p=42
then p=7,r=35
7 fish caught by x
no. caught by y =r
r=5p.
r+p=42
then p=7,r=35
7 fish caught by x
12 :: Two lemons cost 10 cents. Then one and a half dozen cost
90 cents
Ans :
2L=1O => 1L=5
THEN,1 1/2 DOZEN=18L
SO,18L=18*5=90CENTS
2L=1O => 1L=5
THEN,1 1/2 DOZEN=18L
SO,18L=18*5=90CENTS
13 :: Find the next number in the series. 1, 0.5, 0.25, 0.125
0.0625
correct answer is 0.0625
because when 1 divide by 2 then we get 0.5 and further divide by 2 then we
get 0.25 and so on
because when 1 divide by 2 then we get 0.5 and further divide by 2 then we
get 0.25 and so on
14 :: If A covers 15 miles in 20 minutes and 20 miles in 30 minutes then find the average speed of A?
average speed=total distance/total time
so answer is 20+15(total dist)/(1/3+1/2)total time in hrs=
35*(6/5)=42miles/hr
so answer is 20+15(total dist)/(1/3+1/2)total time in hrs=
35*(6/5)=42miles/hr
15 :: Sisters age is twice than that of the brother. If the brothers age is six, what is the sisters age after two years?
14 Yrs.
sister=2*brother age
brother=6 years
sister=12(present age)
after 2years sisters's age=14years.
brother=6 years
sister=12(present age)
after 2years sisters's age=14years.
16 :: Y catches 5 times more fishes than X. If total number of fishes caught by X and Y is 48, then number of fishes caught by X?
8
X+Y=48
Y=5X
=> 5X+X=48 =>6X=48 =>X=8
Y=5X
=> 5X+X=48 =>6X=48 =>X=8
17 :: A is 6 times as fast as B and takes 100 days less to complete a work than B. Find the total number of days taken by A and B to complete the work?
A completed work in 100 days before and A is 6 times faster than B..
let total days to work is n.
A=6B;
A=(n-100) days taken to complete the work;
where as B=n days ;
A=(B-100)
therefore B=A+100;
A=6(A+100);
A=6A+600;
-600=6A-A
-600=5A
A=-600/5
A=300
B=400;
let total days to work is n.
A=6B;
A=(n-100) days taken to complete the work;
where as B=n days ;
A=(B-100)
therefore B=A+100;
A=6(A+100);
A=6A+600;
-600=6A-A
-600=5A
A=-600/5
A=300
B=400;
19 :: Which of the following is the odd one? crew, constellation, companion, league, participants?
companion
20 :: Statement A: A & B have same age;
Statement B: B is younger than C;
Inference : A is younger than C;
(a) True
(b) False
(c) Uncertain
since A and B are of same age and B is younger to C so A is also younger to C.
Ans true
Ans true