# Telecommunications Question: **Download Questions PDF**

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## What is the maximal decimal number that can be accommodated in a byte?

a) 128

b) 256

c) 255

d) 512

## Answers:

**Answer #1**

ITS 256.

SINCE, 1 BYTE=8 BITS

THE LOGIC IS 2^8=256(2 TO THE POWER OF 8)

**Answer #2**

255

**Answer #3**

its 255

because it\\'s from 0 to 255 so its 256 numbers but the max is 255

**Answer #4**

its 2^8-1 = 255

in an 8-bit register 0 to 255 devimal numbers can be stored/written

**Answer #5**

255. the maximal base two number is 1111 1111 which converts to 255 in decimal. 256 is wrong answer. However, you can represent a total of 256 unique numbers with 8bits i.e 0 through to 255.

**Answer #6**

answer is 255 because a byte contains 8 bits and maximum value is all 1's i.e 2^7+2^6+.......+2^1+2^0=256+128+64+32+16+8+4+2+1.

**Answer #7**

the answer256 is correct in english terms if the network started with the #1 but instead its european standard is used 0-255 which equals 256.the #256 wouldn't be accepted.Just remember to count starting with 0

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