Question:
What if we call run() method directly instead start() method?

Option A):
Each thread starts in a separate call stack And Invoking the run() method from main thread, the run() method goes onto the current call stack rather than at the beginning of a new call stack
Option B):
Each thread starts in a separate call stack
Option C):
None
Option D):
Invoking the run() method from main thread, the run() method goes onto the current call stack rather than at the beginning of a new call stack

Correct Answer is Option A):
Each thread starts in a separate call stack And Invoking the run() method from main thread, the run() method goes onto the current call stack rather than at the beginning of a new call stack