Logical Question:
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The letters A, B, C, D, E, F and G, not necessarily
in that order,
stand for seven consecutive integers from 1 to 10
D is 3 less than A
B is the middle term
F is as much less than B as C is greater than D
G is greater than F

1. The fifth integer is
(a) A
(b) C
(c) D
(d) E
(e) F

2. A is as much greater than F as which integer is
less than G
(a) A
(b) B
(c) C
(d) D
(e) E

3. If A = 7, the sum of E and G is
(a) 8
(b) 10
(c) 12
(d) 14
(e) 16

Answer:

the list goes:
E F D B C A G
hence,ans
1.b
2.d
2.b

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There are 7 letters A,B,C,D,E,F,G
All are assigned some numbers from 1,2 to 7.
B is in the middle if arranged as per the numbers.
A is greater than G same as F is less than C.
G comes earlier than E.
1) Which is the fourth letter ? ( B / D / F/ E)
2) what is the difference between A and F? ( 3 /4/ 5/ 6)
3 Choose 4 consecutive letters? ( ABCD / BDFE / AEFB / NONE OF THESE )
Let D be the set of all points in the real plane such that |x| + |y| <= 1,
where |x| (respectively |y|) denotes the absolute value of x (respectively y).
Prove that amongst every 5 points in D, there exist two points whose distance
from one another is at most 1.