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How do you find the refractive index of a liquid by using total internal reflection?

Answer:

Using Snell's law, n (1) = (n (2) x sin angle (2)) / sin angle (1).

n (1) = The refractive index of the more optically dense medium.

n (2) = The refractive index of the less optically dense medium.

angle (1) = The critical angle of the two mediums.

angle (2) = 90 degrees since when light is at the critical angle it undergoes total internal reflection.

Since sin 90= 1, this can be ignored, resulting in n (1) = n (2) / sin angle (1)

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