Aptitude Question:
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Given d value of log 3.142 & log 3.143.
To find the value of log 3.141

Answer:

Here given

log 3.142=x, log 3.143=y;

10^x=3.142----------eqn 1

10^y=3.143----------eqn 2

Subtracting eqn 2-1 ;

.001= 10^y-10^x

and again subtracting

3.142-.001 =3.141

the answer is log 3.141=log( 10^x-(10^y-10^x))

log 3.141=log(2*10^x-10^y)

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