Aptitude Question: Download Questions PDF
Find the root of given equation x-2/(x-1)=1-2/(x-2) if possible?
Answer:
Its,easy as we:
are wid: x-1=2/(x-1)-2/(x-2)
x-1=2(x-2)-2(x-1)/(x-1) *(x-2)
x-1=-2/(x-1)(x-2)^3
so, (x^2-2x-1)(x-2)=-2
(x^3-2x^2-x)-(2x^2-4x+2)=-2
(x^3-4x^2+3x-2)=-2
=> x=0 or,
x^2-4x+3=0
=> x=1,x=3
are wid: x-1=2/(x-1)-2/(x-2)
x-1=2(x-2)-2(x-1)/(x-1) *(x-2)
x-1=-2/(x-1)(x-2)^3
so, (x^2-2x-1)(x-2)=-2
(x^3-2x^2-x)-(2x^2-4x+2)=-2
(x^3-4x^2+3x-2)=-2
=> x=0 or,
x^2-4x+3=0
=> x=1,x=3
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