Voice Gateways Question: Download Questions PDF
Do you know What is the maximal decimal number that can be accommodated in a byte?
Answer:
256
SINCE, 1 BYTE=8 BITS
THE LOGIC IS 2^8=256(2 TO THE POWER OF 8)
SINCE, 1 BYTE=8 BITS
THE LOGIC IS 2^8=256(2 TO THE POWER OF 8)
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