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A man walks at 4 km/hr on plain, then at 3 km/hr uphill and then returns through the same road at 6 km/hr downhill and at 4 km/hr on the plain. It takes altogether 6 hours. So what distance he covered in one way?
Answer:
total distance 2 reach up d top and return back =24km!!!
let us consider flat land=x km and slope land=y km
speed @ flat land=4kmph,==> 4km=1hr=>1km=1/4hr
thus, for x km==>x/4hr
speed a@ walkin up @ slope=3kmph==>3km=1hr==>1km=1/3 hr
thus for ykm==y/3hr
speed returning back in slope=6kmph==>6km=1hr==>1km=1/6hr
thus for ykm==y/6hr
thus total hour for travel=x/4 +y/3 +y/6 +x/4 =6 hours
solving , x+y=12km
thus total distance to go to top of hill and return back =12+12=24km :)
let us consider flat land=x km and slope land=y km
speed @ flat land=4kmph,==> 4km=1hr=>1km=1/4hr
thus, for x km==>x/4hr
speed a@ walkin up @ slope=3kmph==>3km=1hr==>1km=1/3 hr
thus for ykm==y/3hr
speed returning back in slope=6kmph==>6km=1hr==>1km=1/6hr
thus for ykm==y/6hr
thus total hour for travel=x/4 +y/3 +y/6 +x/4 =6 hours
solving , x+y=12km
thus total distance to go to top of hill and return back =12+12=24km :)
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